Question

The measure of angle A is 15°, and the length of side

Answer 1

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$