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Svet_ta [14]
4 years ago
15

At the zoo the polar bears are fed from 4 kg bucket of a fish day.If each bears eats 3 upon 5 from that bucket what amount of fi

sh in grams is a bears feed
Mathematics
1 answer:
ser-zykov [4K]4 years ago
6 0

Answer:

2400 grams

Step-by-step explanation:

The bears are fed from a 4 kg bucket each day. If the bears eat 3/5 of that bucket, therefore, the amount of fish that the bears eat is:

3 / 5 * 4 = 2.4 kg

Converting this to grams:

1 kg = 1000 g

2.4 kg = 2.4 * 1000 = 2400 grams

The bears feed is 2400 grams

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Use the unit fractions 36in./1yd and 2.54 cm/1in. Convert 11 yd to cm.
madam [21]

Answer:

1,005.84 cm

Step-by-step explanation:

Given the unit fractions, 36 in/1 yd (i.e. 36 inches = 1 yard), and 2.54 cm/1 in (i.e. 2.54 cm = 1 inches), to convert 11 yd to cm, first convert to inches, then convert what you have in inches to cm.

Thus:

Converting 11 yd to inches:

36 in = 1 yd

11 yd = 36*11 = 396 in

Converting 396 in to cm:

2.54 cm = 1 in

396 in = 2.54*396 = 1,005.84 cm

5 0
3 years ago
You have space in your garden for 50 small flowering bulbs. Crocus bulbs cost $0.25 each and daffodil bulbs cost $0.85 each. You
Doss [256]
Hello,
We can set up two equations and solve the problem.
Let x be Crocus and y be daffodil. So:
x+y=40
.45x+.65y=20.40
Multiply the first equation by -.45 so to eliminate x. So we get:
-.45x-.45y=-18 Now add this to the second equation:
+.45x+.65y=20.40
And we get:
.20y=2.40 Divide each side by .25 to get:
y=12 Now we can find x by plugging 12 for y in the first equation:
x+12=40 Subtract 12 from both sides to get:
x=28
So now we know there are 12 daffodil and 28 crocus.
RJ
7 0
3 years ago
Read 2 more answers
Jayden is on his boat riding through the Cooper River. He spots the Cooper River Bridge at an angle of elevation of 42⁰. If the
andrezito [222]

Answer:

845.2 it no that hard

3 0
3 years ago
what is the solution to the following system of equations (3x-4y=-25)( 3x+ 4y=5)? PLEASE HURRY!!!!!!!!!!!
babunello [35]
\underline{+\left\{\begin{array}{ccc}3x-4y=-25\\3x+4y=5\end{array}\right}\\.\ \ \ \ \ \ 6x=-20\ \ \ \ |:6\\\\x=-\dfrac{20}{6}\\\\x=-\dfrac{10}{3}
substract the value of x to the second equation:
3\cdot\left(-\dfrac{10}{3}\right)+4y=5\\\\-10+4y=5\ \ \ |+10\\\\4y=15\ \ \ \ |:4\\\\y=\dfrac{15}{4}
\left\{\begin{array}{ccc}x=-\dfrac{10}{3}\\\\y=\dfrac{15}{4}\end{array}\right
3 0
3 years ago
For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. Minitab was used
kkurt [141]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Correlation Coefficient (r) = 0.989

alph=0.05

Number of observations (n) = 8

determine if there is a linear correlation between chest size and weight.

Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.

What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?

To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.

r^2 = square of the correlation Coefficient

r^2 = 0.989^2 = 0.978121

Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.

4 0
4 years ago
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