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Arada [10]
3 years ago
11

Factors of 28 and 44

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0
28= 1,2,4,7,14,28,   

44=1,2,4,11,22,44,
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Two systems of equations are shown below:
Sati [7]
System A:
6x + y = 2
-x - y = -3

System B:
2x - 3y = -10
-x-y = -3

Solve:
System A:
6x + y = 2
y = 2 - 6x
-x - (2-6x) = -3
-x - 2 + 6x = -3
5x = -3 + 2
5x = -1
x = -1/5
y = 2 - 6(-1/5)
y = 2 + 6/5
y = 2 + 1.2
y = 3.2     System A: x = -1/5 or -0.2  ; y = 3 1/5 or 3.2

System B:
2x - 3y = -10
2x = -10 + 3y
x = -5 + 1.5y
-x - y = -3
-(-5 + 1.5y) -y = -3
5 - 1.5y - y = -3
-2.5y = -3 - 5
-2.5y = -8
y = 3.2
x = -5 + 1.5(3.2)
x = -5 + 4.8
x = -0.2   System B: x = -0.2 ; y = 3.2

<span>B) They will have the same solution because the first equations of both the systems have the same graph.</span>

6 0
3 years ago
Read 2 more answers
Where do you find a vertical shift in the exponential parent function?
Montano1993 [528]

For the given expressions we will have:

y = exp(x - 4)   →we have a shift of 4 units to the right.

y = exp (x +9)  → we have a shift of 9 units to the left.

y = exp(x) + 7 → we have a shift of 7 units up.

y = exp(x) - 6  → we have a shift of 6 units down.

<h3>How to work with vertical and horizontal shifts?</h3>

Remember that the shifts work as follows.

For a function f(x), we define a vertical shift of N units as:

g(x) = f(x) + N

  • If N > 0, the shift is upwards.
  • If N < 0, the shift is downwards.

For a function f(x), we define a horizontal shift of N units as:

g(x) = f(x + N)

  • If N > 0, the shift is to the left.
  • If N < 0, the shift is to the right.

Then, if we have:

exp(x - 4) we have a shift of 4 units to the right.

exp (x +9) we have a shift of 9 units to the left.

exp(x) + 7 we have a shift of 7 units up.

exp(x) - 6  we have a shift of 6 units down.

Learn more about translations

brainly.com/question/24850937

#SPJ1

4 0
1 year ago
A protein mix claims to contain a bonus of 20% more mix than the usual size container. If the bonus size contains 18 ounces of m
agasfer [191]

Answer:

The usual size of the container is 15 ounces.

Step-by-step explanation:

Consider the provided information.

A protein mix claims to contain a bonus of 20% more mix than the usual size container.

Let the usual size of the container was x ounces.

They increase 20% of usual size and the bonus size is 18 ounces.

Therefore, the new size should be:

x+20\%x=18

x(1+0.20)=18 (∴20%=\frac{20}{100}=0.20)

x(1.20)=18

x=\frac{18}{1.20}

x=15

Hence, the usual size of the container is 15 ounces.

3 0
3 years ago
If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] 2.<br><br> 1<br> 2<br> 9
uysha [10]
(2)2+1=5

3(1)+1=4 is your answer


5 0
3 years ago
Suppose that a factory manufactures only tables and chairs and that the profit on one chair is $15 and on the table is $20. Each
Leya [2.2K]

Answer:

The data we have is:

Profit per chair = $15

Profit per table = $20

Chair needs: 1 large pice, 2 small pieces.

Table needs: 2 large pieces, 2 small pieces.

You have 6 large pieces and 8 small pieces, and you want to maximize the profit.

Let's define:

T = # of tables

C = # of chairs.

Total profit:

P = C*$15 + M*$20

The number of chairs that you can make is given by:

0 ≤ C ≤ 4

If you make 4 chairs, the profit is:

P = 4*$15 = $60

And there will be 2 large pieces left.

Now for the tables.

0 ≤ T ≤ 3

If you make 4 tables, the profit will be:

P = 3*$20 = $60 (same as before)

And there will be two small pieces left.

Then we want to use a medium number of tables and chairs, we can not use the maximum for any of those, the first thing we should try is:

we ideally would want to use all the pieces that we have.

8 small, 6 large:

Then we can make:

2 tables: we use 4 large pieces and 4 small pieces.

T = 2

And we have left 2 large pieces and 4 small pieces.

The leftover is enough to make two chairs.

C = 2.

In this case, where we used all our materials, the profit will be:

P = 2*$15 + 2*$20 = $30 + $40 = $70

The profit is maximized when we make 2 tables and two chairs.

5 0
3 years ago
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