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3 years ago

Factors of 28 and 44

Mathematics

1 answer:

erastovalidia [21]3 years ago

5 0

28= 1,2,4,7,14,28,

44=1,2,4,11,22,44,

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How do you find x? and how do you round to the nearest tenth?

expeople1 [14]

Hey there!

In order to solve this problem, we can use the Pythagorean Theorem, which is $c^2 = a^2 + b^2$ . Since the Pythagorean Theorem would find only half of the length of x, we'll need to double it in the end.

First, let's plug in what we know to the Pythagorean Theorem: $2.1^2 = 1.4^2 + b^2$

Next, we'll simplify to that $b^2$ is by itself:

$b^2 = 2.45$

Then, we'll find the square root of 2.45, multiply that by 2 and round to the nearest tenth:

$2(\sqrt{2.45} ) = 3.1$

Therefore, x = 3.1 ft.

How to round to the nearest tenth:

In a decimal, the tenth is the first number after the decimal point. To round to the tenth, if the number in the hundredth place is less than 5, you keep the number as it is, but if the number in the hundredth place is more than 5, you increase the number in the tenth place by 1.

Hope this helps!! :)

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3 years ago

A factory produces 70 toys per hour. The relationship between the number of toys produced, t, and the number of hours elapsed, h

MrRissso [65]

B) t = 70 h

A factory produces 70 toys per hour. The relationship between the number of toys produced, t, and the number of hours elapsed, h, is proportional.

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3 years ago

15. Find to the nearest degree the measure of the acute angle that the graph

Vikentia [17]

Check the picture below.

make sure your calculator is in Degree mode.

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3 years ago

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Blizzard [7]

There’s nothing showing up. I think you didn’t add a picture

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2 years ago

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In a state lottery game you select six numbers from 1 to 44. the state selects six numbers at random from 1 to 44 without replac

LiRa [457]

We need to correctly choose exactly 4 out of the 6 drawn numbers.

Apply hypergeometric distribution:
a=number of correctly chosen numbers = 4
A=number of correct (drawn) numbers = 6
b=number of incorrectly chosen numbers = 2
B=number of undrawn numbers = 44-6 = 38

Then by the hypergeometric distribution
P(a,b,A,B)
=C(A,a)C(B,b)/C(A+B,a+b) [C(n,r)=combination of r objects taken out of n]
=C(6,4)C(38,2)/C(44,6)
=15*703/7059052
= 10545/7059052
= 0.001494 (to the nearest millionth)
Answer: probability of winning third prize is 10545/7059052=0.001494

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2 years ago