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Scorpion4ik [409]
3 years ago
15

A website charges $ 0.99 to download a game and $12.49 membership fee. Write an expression that gives the total cost in dollars

to download any number of games.
Mathematics
2 answers:
Zina [86]3 years ago
7 0
0.99+12.49x or 0.99x+12.49
cricket20 [7]3 years ago
6 0

Answer:

12.49+0.99x

Step-by-step explanation:

0.99 per game, x is the amount of games, and 12.49 is the one time membership fee

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SOMEONE PLEASE HELP! I'LL THANK YOU AND RATE 5 STARS AND MARK BRAINLIEST IF I CAN!!
viktelen [127]
Slope of AB=(2-3)/(1+1)=-1/2; AC=(-1-3)/(-3+1)=-4/-2=2; BC=(-1-2)/(-3-1)=-3/-4=3/4.
The product of two sides that are perpendicular is -1. Slopes of AB and AC are perpendicular so angle A is a right angle. ABC is a right-angled triangle.
8 0
3 years ago
Simplify the following 6(1/2+1/3)​
gogolik [260]

Answer:

5

Step-by-step explanation:

use the distributive property

6 * 1/2 = 3

6 * 1/3 = 2

3 + 2 = 5

<em><u>Hope this helped! Have a nice rest of ur day! Plz mark as brainliest!!!</u></em>

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8 0
3 years ago
2,4,4,6,10,11,12<br> Median:<br> Mean:<br> Range:<br> Mode:
maw [93]

Answer:

Median: 6

Mean: 7

Range:10

Mode:4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
6. Sketch the region enclosed by the graphs of x =0, 6y-5x=0 and x+3y=21. Find the area
kow [346]
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h

1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6

Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50

3 0
3 years ago
Read 2 more answers
HELPP!!
SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0
3 years ago
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