The noble gas notation is as follows- you must start with the noble gas that is before the element which in this case is Krypton and then from there you continue the electron configuration as follows- [Kr] 5s^2 4d^10 5p^2
Answer:
proton and electrons orbit close together around a center nucleus
Reactants are what you put into a reaction (the things that react)
Products are the things that come out of a reaction (the things that are produced)
The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.
<h3>Oxidation and reduction</h3>
Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.
In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in 
while that of C in CO changed from +2 to +4 in 
.
Thus, NO is acting as the oxidizing agent while CO is acting is the reducing agent.
More on oxidation and reduction can be found here: brainly.com/question/13699873
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Answer:
a) 2 (H+) ions
b) 1 (SO3²-) ions
c) 1.36 × 10^-22 grams.
Explanation:
According to this question, sulfurous acid has a chemical formula; H2SO3. It is made up of hydrogen and sulfite ion. Hydrogen ion (H+) is the cation while sulfite ion (SO32-) is the anion.
Based on the chemical formula, there are 2 moles of hydrogen ions that reacts with 1 mole of sulfite ion as follows:
2H+ + SO3²- → H2SO3
Hence;
- there are 2 hydrogen ions (2H+) present in H2SO3.
- there is 1 sulfite ion (SO3²-) present in H2SO3.
c) The mass of one formula unit of H2SO3 is calculated thus:
= 1.008 (2) + 32.065 + 15.999(3)
= 2.016 + 32.065 + 47.997
= 82.08 a.m.u
Since, 1 gram is = 6.02 x 10^23 a.m.u
82.08 a.m.u = 82.08/6.02 × 10^-23
= 13.6 × 10^-23
= 1.36 × 10^-22 grams.
