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ExtremeBDS [4]
2 years ago
6

Gold is a better conductor of electricity than copper.

Chemistry
2 answers:
anastassius [24]2 years ago
7 0

Answer:

I would say because gold is more valuable than copper. plus it is harder to find.

Explanation:

Dima020 [189]2 years ago
4 0
From what I remember in high school, they said that since gold is more expensive and not that easy to find, we try to use something that is in the same category and copper is the closest to it and also not expensive and not hard to find.
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Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th
aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = ?

Depression in freezing point = \Delta T_f

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  non electrolyte)

\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg

\Delta T_f=11^oC

\Delta T_f=T- T_f

T_f=T- \Delta T_f=179^oC-11^oC=168^oC

168°C is the melting point of your impure sample.

4 0
3 years ago
1. Identify the type of ecosystem service being provided in each of the following
Wittaler [7]

The ecosystem services provided by the each of the given examples are as follows:

  • A cornfield in Kansas provides provisioning services.
  • Bacteria that decompose waste along the Gulf Coast provides regulating services.
  • Ocean currents that keep Pacific Northwest air cool and moist provides regulating services.
  • Flower garden at a national landmark provides cultural services.
  • Lumber from an oak tree provides provisioning services.
  • Animals that eat seeds and then spread the seeds through their waste regulating services.

<h3>Ecosystem services</h3>

Ecosystem services are defined as the benefits derived by man from the surroundings ecosystems.

<h3>Categories of ecosystem services</h3>

The four categories of ecosystem services are:

  • regulating services,
  • provisioning services,
  • cultural services, and
  • supporting services

A cornfield in Kansas provides provisioning services.

Bacteria that decompose waste along the Gulf Coast provides regulating services.

Ocean currents that keep Pacific Northwest air cool and moist provides regulating services.

Flower garden at a national landmark provides cultural services.

Lumber from an oak tree provides provisioning services.

Animals that eat seeds and then spread the seeds through their waste regulating services.

Learn more about ecosystem services at: brainly.com/question/2191258

7 0
2 years ago
Need help don’t understand this??!
ale4655 [162]

Answer:

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Indonesia. ...

Philippines. ...

Turkey. ...

New Zealand. ...

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7 0
2 years ago
Read 2 more answers
Nh4i(aq)+koh(aq)→ express your answer as a chemical equation. identify all of the phases in your answer.
tester [92]
NH4I (aq)  +  KOH  (aq)  in   chemical   equation  gives

   NH4I (aq)  +  KOH (aq)   =  KI  (aq)  +  H2O(l)  +  NH3  (l)

Ki  is  in  aqueous  state  H2o   is  in   liquid  state  while  NH3  is  in  liquid  state

from  the  equation  above  1 mole of  NH4I (aq) react  with  1 mole of KOH(aq) to  form  1mole of KI(aq) ,  1mole of H2O(l)  and 1  Mole  of NH3(l)
5 0
3 years ago
Read 2 more answers
Use the given heats of formation to calculate the enthalpy change for this reaction. B2O3(g) + 3COCl2(g) →2BCl3(g) + 3CO2(g) ΔHo
UkoKoshka [18]

Answer:

the enthalpy change for this reaction is -57.7 kJ/mol

Explanation:

Given:

HB₂O₃ = -1272.8 kJ/mol

HCOCl₂ = -218.8 kJ/mol

HBCl₃ = -403.8 kJ/mol

HCO₂ = -393.5 kJ/mol

Those are all standard enthalpies

Question: Calculate the enthalpy change for this reaction, ΔHreaction = ?

The enthalpy of the reaction is calculated using the standard enthalpies of formation of both products and reagents. To understand better, the reaction is as follows

B₂O₃ + 3COCl₂ → 2BCl₃ + 3CO₂

Where the compounds on the left are the reactants and the compounds on the right are the products

ΔHreaction = ∑ΔHproducts - ∑ΔHreactants

delta(H)_{reaction} =((2*(-403.2)+(3*(-393.5))-((1*(-1272.8)+(3*(-218.8))=-57.7kJ/mol

Please be careful with the signs.

4 0
3 years ago
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