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3 years ago

If anyone can answer all these questions you can get 35 points

Chemistry

1 answer:

torisob [31]3 years ago

5 0

Answer:

6) 225.8 g

7) 1.01 g

8) 21.624 g

Explanation:

6) Molar Mass of Lithium Bromine: 86.845

86.845 * 2.6 = 225.8 g

7) Molar Mass of Neon: 20.180

20.180 * 0.05 = 1.01 g

8) Molar Mass of Water Vapor: 18.02

18.02 * 1.2 = 21.624 g

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60.0 g of NH Cl are dissolved in 100 grams of water at 60.0° C. This solution is

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Answer:

B) is the correct answer

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What does air have to do with light refraction?

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3 years ago

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A chemist carefully measures the amount of heat needed to raise the temperature of a 894.0g sample of a pure substance from to −

astraxan [27]

Answer:

C = 0.2349 J/ (g °C)

Explanation:

Mass, m = 894.0g

Initial Temperature = −5.8°C

Final Temperature = 17.5°C

Temperature change = 17.5°C - (−5.8°C) = 23.3

Heat, H = 4.90kJ = 4900 J

Specific heat capacit, C = ?

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C = H / mΔT

C = 4900 / (894)(23.3)

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3 years ago

What is the molarity of the solution produced when 8.0g NaOH is dissolved in sufficient water to prepare 500.mL of solution?

Sindrei [870]

Answer:

Molarity = 0.4M

Explanation:

Molar mass of NaOH (M)= 40

m= 8g, V= 500ml=0.5L

n= m/M=[8/40]= 0.2mol

Applying

n= CV

0.2= C×0.5

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8 0

3 years ago

What volume of 24% trichloroacetic acid (tca) is needed to prepare eight 3 ounce bottles of 10% tca solution?

Sever21 [200]

Answer:

295.7 mL of 24% trichloroacetic acid (tca) is needed .

Explanation:

Let the volume of 24% trichloroacetic acid solution be x

Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces

= 24 ounces = 709.68 mL

(1 ounces = 29.57 mL)

Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

$x\times \frac{24}{100}=709.68 mL\times \frac{10}{100}$

x = 295.7 mL

295.7 mL of 24% trichloroacetic acid (tca) is needed .

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3 years ago