<h3><em><u>Answers With Steps:</u></em></h3><h3>Question 1:</h3>
For the first problem, understand that you are solving for the area of a circle. The equation for the area of a circle is pi r². By using the leash length as the radius (r), you can get the answer. (The leash length is 3 meters long.)
<em>Question 1 Steps:</em>
pi 3² ---> pi * 9 ---> ≈28.27
<em>Question 1 Answer:</em>
It would have about 28.27 meters² of playable space.
<h3>Question 2:</h3>
For the second problem, it would be much the same as to the first question. There is the same objective to find the area of the circle. Along with that, it gives us a length to work with. This time it is the sprinkler's reach, which would be the radius, or "r" in the equation.
<em>Question 2 Steps:</em>
pi 5² ---> pi * 25 ---> ≈78.54
<em>Question 2 Answer:</em>
The sprinkler would have about 78.54 feet² of space that it can reach.
Answer:
D).
Step-by-step explanation:
ln (e · e^x) = x2 + 4x + 3
ln e^(x+1) = x^2 + 4x + 3
Taking all terms to the power e:
e^(x + 1 )= e^ (x^2 + 4x + 3)
x + 1 = x^2 + 4x + 3
x^2 + 3x + 2 = 0
(x + 2)(x + 1) = 0
x = -2, -1.
Answer:
you have to finish the question
Step-by-step explanation:
Step-by-step explanation:
I'm sorry
i dont know this particular question
A translation down to the left since it’s negative
