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3 years ago

Answer question 1 and 2 and i’ll give a brainliest to the person with the correct answer

Mathematics

2 answers:

andrezito [222]3 years ago

6 0

Answer:

1.90 2.6

Step-by-step explanation:

TiliK225 [7]3 years ago

3 0

Sushshgehehehrhetregegegeueheheh

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Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

3 years ago

The question is find x

Allushta [10]

Answer:

x = 8

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{BC}{EF}$ = $\frac{CD}{FG}$

Note that ΔBCD is a 3- 4- 5 triangle ( Pythagorean triple), hence CD = 4

Substitute given values into the equation

$\frac{3}{6}$ = $\frac{4}{x}$ ( cross- multiply )

3x = 24 ( divide both sides by 3 )

x = 8

8 0

3 years ago

PLEASE HELP FAST! I'll mark as brainliest

NeX [460]

Answer:

It is easy you just add all of the up and the answer will give you 20 so your answer will be 20

Step-by-step explanation:

ad 2+3+4+5+6 = 20

6 0

3 years ago

Read 2 more answers

What is the smallest positive integer for x so that f(x)=200(2)* is greater than the value of g(x)=500x+400?

Goshia [24]

We have to functions, namely:

$f(x)=200(2)^{x} \ and \ g(x)=500x+400$

So the problem is asking for the smallest positive integer for $x$ so that $f(x)$ is greater than the value of $g(x)$ , that is:

$f(x)\ \textgreater \ g(x) \\ \therefore 200(2)^{x}\ \textgreater \ 500x+400$

Let's solve this problem by using the trial and error method:

$for \ x=1 \\f(1)=400 \\ g(1)=900 \\ Then \ f(1) \ \textless \ g(1) \\ \\ \\ for \ x=2 \\f(2)=800 \\ g(2)=1400\\ Then \ f(2)\ \textless \ g(2) \\ \\ \\ for \ x=3 \\f(3)=1600 \\ g(3)=1900 \\ Then \ f(3)\ \textless \ g(3) \\ \\ \\ for \ x=4 \\f(4)=3200 \\ g(4)=2400 \\ \boxed{Then \ f(4)\ \textgreater \ g(4)}$

So starting $x$ from 1 and increasing it in steps of one we find that:

$f(x)>g(x)$

when $x=4$

That is, the smallest positive integer for $x$ so that the function $f(x)$ is greater than $g(x)$ is 4.

8 0

3 years ago

Which box plot represents a symmetrically distributed data set?

VashaNatasha [74]

The answer i think it is, is C

4 0

3 years ago

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