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Sergio039 [100]
2 years ago
8

Find the solutions of (x² − 9)(x² − 16) =0.

Mathematics
1 answer:
MrMuchimi2 years ago
3 0

Answer:

-3,3 or -4,4

Step-by-step explanation:

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PLEASE HELP!<br>Calculate $40^{13} \pmod{85}.$
SVEN [57.7K]
In this type of calculations, we decompose 13 by checking the lowest powers of the base, that is 40. for example we check 40^2, or 40^3 and compare it to 85

Notice

40*40*40=64,000

so we check how many time does 85 fit into 64,000:

64,000/85=752.94

85*753=64,005;       64000-64,005=-5

this means that 

40^{3} =-5\pmod{85}

thus

40^{13} =40^{3*4+1}={(40^{3})}^{4}*40=(-5)^{4}*40 \pmod{85}=\\\\625*40\pmod{85}=(7*85+30)*40\pmod{85}=30*40\pmod{85}\\\\=1200\pmod{85}=(14*85+10)\pmod{85}=10\pmod{85}


Answer: 10 (mod85)

Remark, the set of all solutions is:

{......-75, 10, 95, .....}, that is 85k +10
7 0
3 years ago
Evaluate \dfrac{e}{4}+2f-3 4e +2f−3 when e=12e=12 and f=\dfrac12f= 21<br> ​
dusya [7]

Answer:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5


Step-by-step explanation:


7 0
3 years ago
Find z1z2 if z1 = 2/5(cos63° + isin63°) and z2 = 10/3(cos117° + isin117°).
Airida [17]

Answer:

-10/3 is the answer

Step-by-step explanation:

Given are two complex numbers as

z1=\frac{2}{5} (cos63  + isin63)\\z2=\frac{10}{3} (cos 117 + isin117})

Recall Demoivre theorem as

(cosA+isinA)(cos A+isin B) = cos(A+B)+isin(A+B)

Hence here we have sum of angles  as

A+B = 63+117 =180

z1z2=\frac{2}{5} \frac{10}{3} (cos180+isin180)

=\frac{-10}{3}

Since sin180=0 and cos 180=-1

7 0
3 years ago
A list of numbers is given <br><br><br> 32,16,8,4,2,1<br><br> Write a rule for the pattern
Sphinxa [80]
It is subtracting the current number by 1/2    OR you can divide by 2. each time.

32 / 2= 16
16 / 2=8
8/2=4
4/2=2
2/2=1

Hope this helped!
5 0
3 years ago
Read 2 more answers
What is the answer to thus problem z=y-x
anastassius [24]
The only answers that are possible is z=y-x y=x+z or x=y-z
6 0
3 years ago
Read 2 more answers
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