The first thing you want to do is isolate the (x)s.
Of course you need to know what "gross margin percentage" means.
Roughly speaking it is the profit as a percentage of sale price.
When a unit costs $1.00 and is sold at $2.50 the excess revenue is $1.50
Although we could express this profit margin as a FRACTION of the sale price,
(so this would be 1.50/2.5 = 3/5), it is usual to state this as a PERCENTAGE.
The gross margin percentage in the original case would be 100 * 3/5 = 60%
Let cost price be c, sale price be s.
Gross margin percentage g = 100* (s - c)/s
Solving this for sale price s
s = c/[1 - (g/100)]
When unit cost increases $0.25 we have c = 1.25
so s = 1.25[1 - 0.6] = 1.25/0.4 = 3.1
Action needed to maintain the gross margin percentage
is to increase selling price to $3.10
Answer:
What is the question?
Step-by-step explanation:
T=time
d=st
r=train speed
p=plane speed
<span>160=rt
</span><span>720=pt
speed of plan is 20kmph less than 5 times speed of train
p=5r-20
we notice that 160 times 4.5=720
times first equaton by 4.5
720=4.5rt
720=pt
set equal
4.5rt=pt
divide both sides by t
4.5r=p
sub </span><span>p=5r-20 for p
4.5r=5r-20
minus 4.5r from both sides
0=0.5r-20
add 20 to both sides
20=0.5r
times 2 both sides
40=r
sub back</span><span>
p=5r-20
p=5(40)-20
p=200-20
p=180
plane is 180kmph
train is 40kmph
</span>
