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Citrus2011 [14]
4 years ago
10

While running a 100m race, a runner runs from the 20m to 30m mark in 77 frames of a video record. If the video camera recorded d

ata at 50 frames/s, how fast was she running during the video interval (in m/s)
Physics
1 answer:
Marrrta [24]4 years ago
3 0

Answer:

Speed of the runner during video interval is 6.49 m/s

Explanation:

According to the problem,

Number of frames recorded by camera in 1 second = 50

Time takes by camera to record 1 frame = (1/50) s

Time taken by camera to record 77 frames, t = \frac{1}{50}\times 77 s

Distance covered by the runner during the video recording, d = 10 m

Speed, v = \frac{Distance}{time}=\frac{d}{t}

Substitute the values of d and t in the above equation.

v = \frac{10}{\frac{77}{50} }

v = 6.49 m/s

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A rocket accelerates at 25m/s^2 for 5s before it runs out of fuel and dies. What is the maximum height reached by the rocket?
sineoko [7]

Answer:

1109m

Explanation:

The distance h₁ traveled by the rocket during acceleration:

h_1=\frac{1}{2}at^2

The velocity v₁ at this height h₁:

v_1=at

When the rocket runs out of fuel, energy is conserved:

E=\frac{1}{2}mv_1^2+mgh_1=mgh_2

Solving for h₂:

h_2=\frac{v_1^2}{2g}+h_1=\frac{(at)^2}{2g}+\frac{1}{2}at^2

8 0
3 years ago
Pablo rode a skateboard up a ramp for a distance of 3.8 m. If the ideal mechanical advantage of the ramp is 2, how far above the
Vika [28.1K]
The answer is 1.9 m

The ideal mechanical advantage (IMA) is the ratio of input distance (ID) to output distance (OD):
IMA = ID/OD
IMA = 2
ID = ramp length = 3.8 m
OD = height = ?

2 = 3.8m/OD
OD = 3.8/2
OD = 1.9 m
4 0
3 years ago
a plane being propelled due east is actually moving at 225mph an angle of 40 degrees north of east, how fast is the crosswind th
Marianna [84]

Answer:

144.63 mph

Explanation:

225 sin (40)

4 0
4 years ago
Help me please this is for physics
Yuri [45]
<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

23.1m/s

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

T=\frac{2_{v0~sin 0} }{g}

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}

⇒ 2 ×_{v0} ×0.8910= 9.8 × 4.2

⇒\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}

\boxed{{v0} =23.1m/s}

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

3 0
3 years ago
Which one of the following equations correctly represents the process relating to the ionization energy of X?
Naily [24]

Answer:

The correct option is E. X(g) → X⁺(g) + e⁻

Explanation:

The electrons are attracted to the nucleus and it is necessary to provide energy to start them. Then the ionization energy is the energy necessary to pull an electron to a gaseous atom, isolated and in a fundamental state. The electrons in the last shell are the most weakly attracted to the nucleus, so these are the lost electrons.

In this way, the gaseous element is converted to a gaseous cation (positively charged ion).

Taking this definition into account, <u><em>the correct option is E. X(g) → X⁺(g) + e⁻</em></u>

7 0
3 years ago
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