1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vinil7 [7]
3 years ago
12

How many miles of MgCI2 are there in 339g of compound?

Physics
1 answer:
harkovskaia [24]3 years ago
4 0

I'm going to answer this by using rounded numbers for the atomic masses. You need only go back and put the numbers in from your periodic table. My answers will be close, but not what you should get.

Find the Molar Mass of MgCl2

Mg =                   24 grams

2Cl = 2 * 35.5 = 71 grams

Total  =              95 grams

Find the mols in 339 grams

1 mole = 95 grams

x mol = 339

Solve

339 = 95x   Divide by 95

339/95 = x

x = 3.67 mols  Answer

You might be interested in
Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 20.0 m above water wit
madam [21]

Answer:

The initial energy and final energy are the same

= 307.52m

≅ 308m

Explanation:

see the attached file

6 0
4 years ago
As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the
Sever21 [200]

Answer:

a

   a =  12.32 \  m/s^2

b

 F = 1017.52 \  N

Explanation:

From the question we are told that

  The  length of the Chinook salmon is  l =  1.50 \  m

   The mass of the Chinook salmon is m  =  46.0 \ kg

   The  upward velocity in water is  u =  3.00 \ m/s

    The  upward velocity in air is v =  5.80 \ m/s

   

Generally from kinematic equations

     v^2  =  u^2 +  2as

=>    5.80^2  =  3.00^2 +  2  *  a *  [ [\frac{2}{3} * l ]

=>   5.80^2  =  3.00^2 +  2  *  a *  [ [\frac{2}{3} * 1.5 ]

=>   5.80^2  =  3.00^2 +  2  *  a *  [1 ]      

=>    a =  12.32 \  m/s^2

Generally magnitude of the force F during this interval in N  is mathematically represented as

      F  =  m (a + g )

=>    F  =  46.0 (12.32 + 9.8 )

=>    F = 1017.52 \  N

5 0
4 years ago
Sharece knows that wave peaks and valleys can add and subtract. What would be the net effect if she was able to cross Wave 1 (a
levacccp [35]

Answer:

The two waves will add vectorially to produce a small amplitude wave in a valley phase.

Explanation:

The two waves will add vectorially to produce a small amplitude wave in a valley phase. This is because the amplitudes of the waves are slightly different and in opposite directions. When wave 1 cancels out all of wave 2, the resultant wave would be the slight difference between both waves, and it would be in the direction of wave 1 which is a valley phase.

6 0
3 years ago
Soap bubbles can display impressive colors, which are the result of the enhanced reflection of light of particular wavelengths f
Bogdan [553]

Answer:

the minimum wall thickness that will enhance the reflection of light is 146.9 nm

Explanation:

Given the data in the question;

At the first interface, a phase shift occurs as the incident light is in air that has less refractive index compare to the thin film of soap bubble.

At the second interface, no shift occurs,

condition for constructive interference;

t = ( m + 1/2) × λ/2n

where m = 0, 1, 2, 3 . . . . . .

now, the condition for the constructive interference;

t = mλ/2n

where t is the thickness of the soap bubble,  λ is the wavelength of light and n is the refractive index of soap bubble.

so the minimum thickness of the film which will enhance reflection of light will be;

t_{min =  ( m + 1/2) × λ/2n

we substitute

t_{min =  ( 0 + 1/2) × 711 /2(1.21)

t_{min = 0.5 × 711/2.42

t_{min = 0.5 × 293.80165

t_{min = 146.9 nm

Therefore,  the minimum wall thickness that will enhance the reflection of light is 146.9 nm

8 0
3 years ago
A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 5.00s what is the speed of the mail
grandymaker [24]
The acceleration of gravity (on Earth) is 9.8 m/s² downward.

This means that every falling object gains 9.8 m/s more downward speed
every second that it falls.

In 5 seconds of falling, it gains (5 x 9.8 m/s) = 49 m/s of downward speed.

If it was already descending at 2.0 m/s at the beginning of the 5 sec,
then at the end of the 5 sec it would be descending at

                                 (2 m/s  +  49 m/s)  =  51 m/s .
7 0
3 years ago
Other questions:
  • What is the mass of the heaviest book this person can hold onto vertically before it slips out of his or her fingers? The coeffi
    6·1 answer
  • A metallic sheet has a large number of slits, 5.0 mm wide and 20 cm apart, and is used as a diffraction grating for microwaves.
    5·1 answer
  • An 8-m-diameter hot air ballooon that has a total mass of 400 kg isstanding still in air on a windless day. The balloon suddenly
    11·1 answer
  • 10 points
    10·1 answer
  • What kind of circuit is the one shown below?
    14·1 answer
  • If an arrow is fired from a bow with a perfectly horizontal velocity of 60.0 m/s and the arrow had a vertical velocity of 6m/s j
    10·1 answer
  • What’s our “blind spot”?
    7·1 answer
  • 8.
    8·2 answers
  • Tom wanted to buy a hunting dog with a waterproof undercoat and a good sense of smell. Which type of genetic engineering would h
    6·1 answer
  • What is the velocity of this graph between points a and b? 0.0m/s 2.5m/s 5.0m/s 6.0m/s?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!