The sum of four times a first number and a second number is 68. If the first number is decreased by twice the second number the
result is -1. Find the numbers.
1 answer:
The first number is 15 and the second number is 8.
<u>Step-by-step explanation</u>:
Let us assume,
- First number be 'x'.
- Second number be 'y'.
<u>Given</u> :
Sum of four times a first number and a second number is 68.
⇒ 4x + y = 68
⇒ y = 68-4x
If the first number is decreased by twice the second number the result is -1.
⇒ x - 2y = -1
Substitute y = 68-4x in the above equation.
⇒ x - 2(68-4x) = -1
⇒ x-136+8x = -1
⇒ 9x - 136 = -1
⇒ 9x = -1+136
⇒ x = 135/9
⇒ x = 15
The first number is 15.
The second number is y = 68-4x.
⇒ y = 68 - 4(15)
⇒ y = 68-60
⇒ y = 8
The second number is 8.
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