Moles = mass / molar mass
<span>moles P = 0.422 g / 30.97 g/mol = 0.01363 mol </span>
<span>moles O = (0.967 g - 0.422g) / 16.00 g/mol = 0.03406 moles </span>
<span>So ratio moles P : moles O </span>
<span>= 0.01363 mol : 0.03406 mol </span>
<span>Divide each number in the ratio by the smallest number </span>
<span>(0.01363 / 0.01363) : (0.03406 / 0.01363) </span>
<span>= 1 : 2.5 </span>
<span>The empirical formula needs to be the smallest whole number ratio of atoms in the molecules. Since you have a non-whole number, multiply the ratio by the smallest number needed to make both number whole numbers. In this case x 2 </span>
<span>2 x (1 : 2.5) </span>
<span>= 2 : 5 </span>
Answer:
Hydrogen has only 1 valence electron in its outermost shell.
Explanation:
Answer is: B₂O₃ + Mg → B + MgO.
B₂O₃ + 3Mg → 2B + 3MgO, balanced.
B₂O₃ - diboron trioxide. White, glassy solid compound.
B - boron. Metalloid, crystalline boron is and amorphous<span> boron is a brown powder.
Mg - magnesium. S</span><span>hiny, gray and solid metal.
MgO - magnesium oxide. W</span><span>hite, </span>hygroscopic<span> solid powder.</span>
Answer:
0.1077 grams
Explanation:
First we will employ the ideal gas law to determine the number of moles of nitrogen gas.
PV=nRT
P=2 atm
V=20L
R=0.08206*L*atm*mol^-1*K^-1
T=323.15 K
Thus, 2atm*20L=n*0.08206*L*atm*mol^-1*K^-1*323.15K
K, atm, and L cancels out. Thus n=2*20mol/0.08206*323.15=1.5 moles
Lastly, we must convert the number of moles to grams. This can be done by dividing the number of moles by the molar mass of nitrogen gas, which is 14 grams.
1.5/14=0.1077 grams
Answer:
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