Question

When an irregular shaped object was put in a graduated cylinder with an initial volume of 25 mL of water, the water level rose to 54.0 mL of water after the object was submerged. If the mass of the object is 7.0 grams, what is the density of the object

Answer 1

Answer:

0.24 g/mL

Explanation:

The density of an object is given by the ratio between its mass and its volume:

$\rho=\frac{m}{V}$

where

m is the mass of the object

V is its density

In this problem, we have:

m = 7.0 g is the mass of the object

The volume of an irregular shaped object can be measured by putting it into water, and by measuring the difference in water volume.

In this case,

$V_1=25 mL$ is the initial volume of water

$V_2=54 mL$ is the final volume of water

So the volume of the object is

$V=V_2-V_1=54-25=29 mL$

Therefore, the density of the object is:

$\rho = \frac{7.0 g}{29 mL}=0.24 g/mL$