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gladu [14]
2 years ago
10

A solution is made by dissolving 2.5 moles of sodium chloride (NaCl) in 198 grams of water. If the molal boiling point constant

for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem.
Chemistry
1 answer:
GREYUIT [131]2 years ago
8 0
Calculate the mol of NaCl dissolved in 1.0kg water :


198 g / 1000 => 0.198 Kg

molality = moles solute / volume 

molality = 2.5 / 0.198

molality = 12.626 mol/kg

NaCl dissociates to form 2 ions 

increase in boiling point = molality * i * Kb

12.626 * 2 * 0.51  => 12.87 ºC

<span>Water boils at 100.00 degrees Celsius , therefore:
</span>
12.87 + 100.00 => 112.87ºC

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1.1 * 10^7 km

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What is the molarity of a solution in which 7.1 g of sodium sulfate is dissolved in enough water to make 100. mL of solution?
Sidana [21]

Answer:

0.50 M

Explanation:

Given data

  • Mass of sodium sulfate (solute): 7.1 g
  • Volume of solution: 100 mL

Step 1: Calculate the moles of the solute

The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

7.1g \times \frac{1mol}{142.02g} = 0.050mol

Step 2: Convert the volume of solution to liters

We will use the relation 1 L = 1000 mL.

100mL \times \frac{1L}{1000mL} =0.100L

Step 3: Calculate the molarity of the solution

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How many moles of Fluorine (F2) are<br><br> needed to completely react 8.0<br><br> moles of NF3?
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Answer:

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Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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From the balanced equation above,

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Finally, we shall determine the number of mole of F₂ needed to produce 8 moles of NF₃. This can be obtained as illustrated below:

From the balanced equation above,

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Therefore, Xmol of F₂ will react to produce 8 moles of NF₃ i.e

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Xmol of F₂ = 12 moles

Thus, 12 moles of F₂ is needed for the reaction.

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