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gladu [14]
2 years ago
10

A solution is made by dissolving 2.5 moles of sodium chloride (NaCl) in 198 grams of water. If the molal boiling point constant

for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem.
Chemistry
1 answer:
GREYUIT [131]2 years ago
8 0
Calculate the mol of NaCl dissolved in 1.0kg water :


198 g / 1000 => 0.198 Kg

molality = moles solute / volume 

molality = 2.5 / 0.198

molality = 12.626 mol/kg

NaCl dissociates to form 2 ions 

increase in boiling point = molality * i * Kb

12.626 * 2 * 0.51  => 12.87 ºC

<span>Water boils at 100.00 degrees Celsius , therefore:
</span>
12.87 + 100.00 => 112.87ºC

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kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

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3 years ago
Which of the following is a balanced chemical equation?
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Answer:

equation number 3 is balanced.

hope it helps ☺️!

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so in 2.33L = 6.7*2.33/1.3 = 12 mol

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