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3 years ago

9

Help meeee i need this right now!!!! 2+2÷(

e=" \sqrt{72} " alt=" \sqrt{72} " align="absmiddle" class="latex-formula">

1 answer:

Andre45 [30]3 years ago

8 0

Answer:

$\frac{1}{3} \sqrt{2}$ or 0.471405

Step-by-step explanation:

$\frac{(2)(2)}{\sqrt{72} }$

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3 years ago

What is 9/10 of 7 inches

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2 years ago

Hours worked 19 hourly rate: $5.75 what is weekly pay

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3 years ago

Read 2 more answers

I need an equation for this problem: A small golf club manufacturer is concerned about their monthly costs. The shop has fixed c

Eduardwww [97]

100 = number of sets of clubs manufactured per month
S = sell-price for a set of clubs

Expenses per month = 23,250 + 145(100) = 37,750

Revenue per month = 100 S

Break-even when Expenses = Revenue

<u>100 S = 37,750</u>

One question: How did you solve it without an equation ?

6 0

2 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

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9 months ago