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3 years ago

Find the mean of 6, 10 graphically.

Mathematics

2 answers:

sergey [27]3 years ago

7 0

Answer:

10 + 6 + 20 = 36 / 3 = 12.

Step-by-step explanation:

The you started studying statistics and all of a sudden the “average” is now called the mean. What happened? The answer is that they are.

dem82 [27]3 years ago

4 0

i just searched this up on math website

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-6-5

tankabanditka [31]

The equation of the line that is parallel to the given line and passes through the point (-2,2) is:

$y = \frac{x}{5} + \frac{12}{5}$

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

When two lines are parallel, they have the same slope. In this problem, the given line passes through (-5,-4) and (0,-3), hence the slope is:

m = (-3 - (-4))/(0 - (-5)) = 1/5.

Hence the equation is:

$y = \frac{x}{5} + b$

When x = -2, y = 2, then:

$y = \frac{x}{5} + b$

$2 = \frac{-2}{5} + b$

$b = \frac{12}{5}$

Hence:

$y = \frac{x}{5} + \frac{12}{5}$

More can be learned about linear equations at brainly.com/question/24808124

#SPJ1

7 0

1 year ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

#3-4 PLEASE HELP ASAP

Pie

Answer:

IDK

Step-by-step explanation:

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4 0

3 years ago

What is the midpoint of the x-intercepts of f(x) = (x – 4)(x + 4)? (0,0) (0,4) (–4,0) (2,0)

forsale [732]

Answer:

The midpoint of the x-intercepts of the function is (0, 0)

Step-by-step explanation:

Notice that since the function comes in factor form, we know that its roots (which are actually the intercepts the function has with the x-axis) are: x = 4 and x = -4 (the x-values for which the function renders zero).

These two points are equidistant from the origin of coordinates (0, 0), and therefore the midpoint of these x-intercepts is (0, 0).

6 0

3 years ago

HELPPP FIND THE AREA !!

Rashid [163]

Answer:

To find the area, you have to multiply its height by its width.

Step-by-step explanation:

7 0

3 years ago