Listing the data from the Stem and Leaves table as raw data we have:
02, 03, 03, 07, 10, 10, 17, 34, 34, 35, 35
Hence the smallest value is 02 = 2
Answer: A
2x - 6y = 12
so we pick any number for x and then solve for y
lets say x = 0
2(0) - 6y = 12
-6y = 12
y = -12/6
y = -2....so when x = 0, y = -2....(0,-2) <== one point
lets say x = 1
2(1) - 6x = 12
2 - 6x = 12
-6x = 12 - 2
-6x = 10
x = -10/6
x = - 5/3...so when x = 1, y = -5/3....(1,-5/3) <== another point
Lets say x = 2
2(2) - 6y = 12
4 - 6y = 12
-6y = 12 - 4
-6y = 8
y = -8/6
y = - 4/3....so when x = 2, y = -4/3.....(2,-4/3) <== another point
lets say x = 3
2(3) - 6y = 12
6 - 6y = 12
-6y = 12 - 6
-6y = 6
y = -6/6
y = -1....so when x = 3, y = -1.....(3,-1) <== another point
now there is 4 points.
Answer:
enter it in a calculator, and you get 6400
Answer:
For purple;
P(p) = 337/848 = 0.40
For white;
P(w) = 511/848 = 0.60
Step-by-step explanation:
Given;
Number of plants with purple flowers P = 337
Number of plants with white flowers W = 511
Total T = 337 + 511 = 848
For purple;
the empirical Probability that a plant had purple flowers P(p) is
P(p) = Number of plants with purple flowers/total number of plants
P(p) = P/T
Substituting the values, we have;
P(p) = 337/848 = 0.40
For white;
the empirical Probability that a plant had white flowers P(w) is
P(w) = Number of plants with white flowers/total number of plants
P(w) = W/T
Substituting the values, we have;
P(w) = 511/848 = 0.60
The tank is leaking at the rate of 6 gallons per hour.
If you do nothing but sit there and watch it all afternoon,
here's what you'll see:
First hour . . . . 6 gallons leaks out
Second hour . another 6 gallons leaks out
Third hour . . . another 6 gallons leaks out
Total gone after 3 hours: (6 + 6 + 6) = 18 gallons .
