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AVprozaik [17]
3 years ago
12

52m when m=105 explain this to me please

Mathematics
2 answers:
JulsSmile [24]3 years ago
5 0
52m when m= 105
52(105)
5,460

so you plug in the 105  next to the 52 and you multiply it and get 5,460.
i hope this helped

Lilit [14]3 years ago
3 0
When you write an alphabet with any no. it means that we are multiplying it with the no. ( here , it means that 52m = 52 * m )

So , 52 * m = 52 * 105
= 5460
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Angle Q = 85° Determine angle O.
kkurt [141]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Please help this for my pre calculus finals
dsp73

Answer:

a) It will take 17.71 years

b) It will take 17.58 years

c) I will earn $6.60 more in compound continuously

Step-by-step explanation:

a) Lets talk about the compound interest

- The formula for compound interest is A = P (1 + r/n)^(nt)

, Where:

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial deposit)

- r = the annual interest rate (decimal)

- n = the number of times that interest is compounded per unit t

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound quarterly

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ n = 4

∴ t = ?

∵ A = P (1 + r/n)^(nt)

∴ 6000 = 2000 (1 + 0.0625/4)^4t ⇒ divide both sides by 2000

∴ 3 = (1.015625)^4t ⇒ insert ㏑ for both sides

∴ ㏑(3) = ㏑(1.015625)^4t

∵ ㏑(a)^b = b ㏑(a)

∴ ㏑(3) = 4t ㏑(1.015625) ⇒ divide both sides by ㏑(1.015625)

∴ 4t = ㏑(3)/㏑(1.015625) ⇒ divide both sides by 4

∴ t = [㏑(3)/㏑(1.015625)] ÷ 4 = 17.71

* It will take 17.71 years

b) Lets talk about the compound continuous interest  

- Compound continuous interest can be calculated using the formula:

  A = P e^rt  

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial amount)

- r = the interest rate  

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound continuously

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ t = ?

∵ A = P e^rt  

∴ 6000 = 2000 e^(0.0625 t) ⇒ divide both sides by 2000

∴ 3 = e^(0.0625 t) ⇒ insert ㏑ to both sides

∴ ㏑(3) = ㏑[e^0.0625 t]

∵ ㏑(e^a) = a ㏑(e) ⇒ ㏑(e) = 1 , then ㏑(e^a) = a

∴ ㏑(3) = 0.0625 t ⇒ divide both sides by 0.0625

∴ t = ㏑(3)/0.0625 = 17.5778

* It will take 17.58 years

c) If t = 5 years

# The compound quarterly:

∵ A = P (1 + r/n)^(nt)

∴ A = 2000 (1 + 0.0625/4)^(4×5)

∴ A = 2000 (1.015625)^20 = $2727.08

# Compound continuously

∵ A = P e^(rt)

∴ A = 2000 e^(0.0625×5) = $2733.68

∴ I will earn = 2733.68 - 2727.08 = $6.60

* I will earn $6.60 more in compound continuously

5 0
3 years ago
5 questions
zzz [600]

This is a comment---

Are you acually in middle school because this is algebra 2 and im learning this now in High school

4 0
3 years ago
I need help with this problem. thank you so much who ever answer this
skelet666 [1.2K]

-36/8 = -4.5

 -4.5  = -4.5

7 0
3 years ago
Read 2 more answers
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