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malfutka [58]
4 years ago
15

Write an equation of a line in slope intercept form with the slope of 8 and a y-intercept of -4

Mathematics
1 answer:
pentagon [3]4 years ago
4 0

Answer:

y=8x-4

Step-by-step explanation:

y=mx+b

m=8

b (y intercept)= -4

y=8x-4

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11. Simplify 3/ 2 - /2
Igoryamba

answer:

you can't simplify that

step-by-step explanation:

3/2- /2 isn't a proper equation, therefore it cannot be simplified

please let me know if the issue is that you forgot the numerator, and in the instance that this is the case please type in the comments the numerator and i'll gladly change my answer

have a nice day!

8 0
3 years ago
If a+8 = 12 , then a =ayuda por favor
NARA [144]

Answer:

a = 4

Step-by-step explanation:

a+8 = 12

a= 12-8

a=4

7 0
3 years ago
Read 2 more answers
Draw a quadratic function below with zeros at -3 and 5 that is also concave up.
tia_tia [17]

Hello from MrBillDoesMath!

Answer:

x^2 - 2 x - 15

Discussion:

( x - (-3)) * ( x- 5) =

(x +3) (x-5) =

x^2 - 2 x - 15

It is a concave upward curve (looks like a "u") as the x^2 term causes the function to grow larger as x approaches +\- infinity.

Thank you,

MrB

8 0
4 years ago
PLSS HELP ME ASNWER THIS! 25 POINTS!
fomenos

Answer:

5.4%

Step-by-step explanation:

percent error = |(measured - actual value) / actual value * 100| = |(7.8-7.4) / 7.4 * 100| ≈ 5.4%

8 0
2 years ago
Read 2 more answers
in a recent year in the united state, 83, 600 passengers car rolled over when they crashed, and 5,127,400 passengers cars did no
alexdok [17]

Answer:

0.01 probability of a car rolling over in a crash.

It is very unlikely for a car to roll over in a crash.

Step-by-step explanation:

Let E be any event.

Then, the probability of happening of an event E = \frac{\textrm{Number of favorable outcomes}}{\textrm{Total Outcomes}}

Now here,

Let E1 = The event where cars rolled when they crashed

E2 =  The event where cars did not roll when they crashed

The number of cars that did roll = 83, 600

The number of cars that did not roll = 5,127,400

So, total  number of cars taken into account for any event

= 83, 600  + 5,127,400 = 5,211,000

So, P(E1)  = 83, 600 / 5,211,000 = 0.01

Hence there is 0.01 probability of a car rolling over in a crash.

and P(E2)  = 5,127,400  / 5,211,000 = 0.98

Since P(E2) is way way more than that of P(E1)

Hence, it is very unlikely for a car to roll over in a crash.

4 0
3 years ago
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