Hi!
To solve this, let's use PEMDAS.
37 - 5 ÷ 2 + 4 · 3 = ?
Multiplication..
37 - 5 ÷ 2 + 12 = ?
Division..
37 - 2.5 + 12 = ?
Addition..
37 - 14.5 = ?
Subtraction..
22.5
The answer is 22.5
Hope this helps! :)
Answer:
7
Step-by-step explanation:
Given the class interval :
Number of Social
Interactions
35-42
43-50
51-58
59-66
67-74
75-82
83-90
91-98
99-106
107-114
The class width = 7
The class width is the range between each class intervals :
42 - 35 = 4
114 - 107 = 7
106 - 99 = 7
Three consecutive integers: Let the first be x. Then the second would be x+1 and the third would be x+2. The sum of these 3 consecutive integers would then be x + x+1 + x+2, or 3x + 3.
Unless you know what this sum is (numerically speaking), you cannot solve this problem for x.
A/B : 4/9 = 12/B
cross multiply
(4)(B) = (9)(12)
4B = 108
B = 108/4
B = 27
P = 4a...where a is the length of one side
P = 4(27)
P = 108 yds <=== perimeter of square B
