4 years ago

what is the equation of the through point (-3,6) that prependicular to the line y=3x-10 in slope intercept form ?

1 answer:

7 0

$y=3x-10\\\\
General\ formula:\\y=ax+b\\\\
Line\ is\ perpendicular when\ new\ a=-\frac{1}{a}\\y=-\frac{1}{3}x+b\\\\
Passes\ through\ (-3,6):\\6=-3(-\frac{1}{3})+b\\6=1+b\ \ \ | subtract\ 1\\b=5\\\\
Equation\ for\ line\ is\ y=-\frac{1}{3}+5
$

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