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kow [346]
3 years ago
10

How to solve instantaneous velocity

Mathematics
1 answer:
Tanya [424]3 years ago
5 0
I don't know the answer I have a party for different symbols and rode with the news of the people i know why you always say that
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Find the volume h=12cm r=5cm
Goshia [24]

If this was a cone, the volume would be 314.16.

  • You would just put in the radius and height in the cone volume formula which is πr²h 1/3

If this is a cylinder then the volume would be 942.48

  • Put in the radius and height in the cylinder volume formula which is πr²h
7 0
3 years ago
Use the given information to find the exact value of the trigonometric function
eimsori [14]
\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}

Half Angle Formula

\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\  \\  \end{gathered}

Answer:

\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}

Checking:

\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{  (3rd quadrant)} \end{gathered}

Also,

\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}

The answer is none of the choices

7 0
1 year ago
Jagroop is building a dock at his cottage. The length of the doc is 3 times the width, plus 2. Determine a simplified expression
MissTica

Answer:

Step-by-step explanation:

Let length = y    width = x

y = 3x + 2

Perimeter = Sum of all sides (or sum of both lengths and both widths)

2y + 2x

2(3x + 2) + 2x

6x + 4 + 2x

8x + 4

7 0
2 years ago
the radius of the center circle of a basketball court is 6 feet. What is the circumference of the center circle.
Elena-2011 [213]
Remember the equation to find the circumference?

Equation of circumference: Pi x 2(radius)

Therefore, 3.141592654 x 2(6ft) = 37.7 feet
6 0
3 years ago
Read 2 more answers
Z varies jointly with x, and y, and z=7 when x= 2, y= 2<br> pleasee I need an answer now!!
Elina [12.6K]

Answer:

(7/4)(2)(2)=7

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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