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3 years ago

How to solve instantaneous velocity

1 answer:

5 0

I don't know the answer I have a party for different symbols and rode with the news of the people i know why you always say that

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B9%20%7Bx%7D%5E%7B2%7D%20%7D%20" id="TexFormula1" title=" \sqrt{9 {x}^{2} } " alt=

Firlakuza [10]

The answer would be 3x i believe
hope this helps! if it doesn't, let me know in the comments! have a great day!

6 0

2 years ago

The two-way frequency table below shows data from a random sample of 93 students on their favourite season and whether or not th

daser333 [38]

Answer:

Choice D

Step-by-step explanation:

8 0

3 years ago

What is the equation of the line with a slope of 3/4 that goes through the point (4, 1) in slope-intercept form?

Svetach [21]

Answer:

$y=\frac{3}{4}x+-2$

Step-by-step explanation:

We do not have enough information for slope intercept form. But we can use the point-slope formula to find the information. The formula is $y -y_{1} =m(x -x_{1})$ where we substitute a point (x,y) for $(x_{1},y_{1})$ .

We have m=3/4 and (4, 1). We input m and $x_{1} =4\\y_{1}=1$ .

$y-1=\frac{3}{4} (x-4)$

We now simplify the parenthesis and solve for y.

$y-1=\frac{3}{4} (x-4)\\y-1=\frac{3}{4}x+\frac{3}{4} (-4)$

We convert -4 into a fraction with 1 as the denominator.

$y-1=\frac{3}{4}x+\frac{3}{4} (\frac{-4}{1} )\\y-1=\frac{3}{4}x+\frac{-12}{4}\\y-1=\frac{3}{4}x+-3$

We add 1 to both sides to isolate y,

$y-1+1=\frac{3}{4}x+-3+1\\y=\frac{3}{4}x+-2$

This is slope intercept form. The line as slope 3/4 and y-intercept (0,2) or b=2.

4 0

3 years ago

SOMEONE PLEASE HELP!!!!!

Harman [31]

Answer:

the answer is A and B

Step-by-step explanation:

hope it helps

5 0

2 years ago

Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)

ElenaW [278]

$\huge\boxed{y-5&=-\frac{1}{3}(x+9)}$

First, we'll find the slope of the new line. The first line has a slope of $3$ . Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by $-1$ ) to get $-\frac{1}{3}$ for the new slope.

Then, we'll use the point-slope form to make the new equation, where $m$ is the slope and $(x_1,y_1)$ is a point on the line:

$\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}$

3 0

1 year ago

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