5600 - 4420 = 1180....so there is a difference of 1180 in a period of (1998 - 1993) = 5 yrs.
1180/5 = 236 people per yr
so in 1998 the population was 5600.....in 2000 (2 yrs later) the population would be : 5600 + 236(2) = 5600 + 472 = 6072 <==
Let x be the number of adults (under 50 years old) after a 12-hour fast where X ~ N(85,25)
The problem is missing some parts but here are the answers:
(a) x is more than 60
z(60) = (60-85)/25 = -1
P(x > 60) = P(z > -1) = 0.158655
(b) x is less than 110
z(110) = (110-85)/25 = 1
P(x < 110) = P(z < 1) = 0.841345
Answer:
338.5
Step-by-step explanation:
5(7.3×9+2)
5(65.7×2)
5×67.7
338.5
I think it makes it more easier if you simplify the inequality.
4x + 20 < 40 First subtract 20 on both sides
4x + 20 - 20 < 40 - 20
4x < 20 DIvide 4 on both sides to get the variable "x" by itself
x < 5 [x is less than 5, so x represents the numbers that are less than 5]
[Note:
If the sign is < or >, you use an open circle.
If the sign is ≤ or ≥, you use a closed circle.]
Your answer is the 1st option because the solution is any number that is less than 5
