A² + b² = c²
a² = c² - b²
a² = 9² - 6²
a² = 81 - 36
a² = 45
a = √45
a ≈ 6.7082
a = 6.7
Answer:
251,502
Step-by-step explanation:
hope it helps!
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Answer:
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The correct form of vector v expressed as a <em>linear</em> combination of the <em>unit</em> vectors i and j is
.
<h3>What is the value of a vector with respect to another vector?</h3>
First, we need to determine the value of the vector u by subtracting two vectors whose <em>initial</em> points are at the origin:
![\vec u = (19\,\hat{i} - 8\,\hat{j}) - (21\,\hat{i} + 12\,\hat{j})](https://tex.z-dn.net/?f=%5Cvec%20u%20%3D%20%2819%5C%2C%5Chat%7Bi%7D%20-%208%5C%2C%5Chat%7Bj%7D%29%20-%20%2821%5C%2C%5Chat%7Bi%7D%20%2B%2012%5C%2C%5Chat%7Bj%7D%29)
(1)
According to the statement, vector v is antiparallel to vector u and its magnitude is five times as the magnitude of vector v, which means that (1) must be multiplied by two scalars:
(2)
Please notice that antiparallelism is represented by the scalar - 1, whereas the dilation is represented by the scalar 5.
![\vec v = 10\,\hat{i} + 100\,\hat{j}](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%2010%5C%2C%5Chat%7Bi%7D%20%2B%20100%5C%2C%5Chat%7Bj%7D)
The correct form of vector v expressed as a <em>linear</em> combination of the <em>unit</em> vectors i and j is
.
<h3>Remark</h3>
The statement presents typing mistakes, correct form is shown below:
<em>Vector u has initial points at (21, 12) and its terminal point at (19, - 8). Vector v has a direction opposite that of u, whose magnitud is five times the magnitud of v. Which is the correct form of vector v expressed as a linear combination of the unit vectors i and j?</em>
To learn more on vectors: brainly.com/question/13322477
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Step-by-step explanation:
if we are taking in terms of domain.. is d set of number that we can put to the function with get division by zero .. squaroot of negative number,log of zero e.t.c
A) p(x)/m(x)= 1/squaroot(x) ÷ x²-4 which we know that x²-4 must not be equal to zero
because if is equal to zero we will have division by zero, which have contradicted the hypothesis of law of domain
x²-4 =! 0
(x-2)(x+2)=!0
x=!2 or x=!-2 because if is equal to that it's has contradicted d hypothesis
the answer is all real number except -2 and -
2
B)p(m(x))=p(x²-4) =1/squaroot of x²-4
note they are two things involve we must not get division by zero and root of negative number
we have all real number expect from -2 to 2
C)m(p(x))=m(1/root of (x))=(1/root of (x))²_4)
we have 1/x-4
so the answer is all real number expect zero