All categories

3 years ago

Which of these is NOT a type of natural force? A) gravity B) friction C) throwing D) magnetism

Chemistry

2 answers:

vesna_86 [32]3 years ago

6 0

Answer:

C- throwing

Explanation:

You physically have to throw it while the other forces act on their own.

zlopas [31]3 years ago

3 0

Throwing isn't classified as a force so I'd say C but it is a force just not a type

You might be interested in

Brenda creates an animation that tells the story of a metal from when it is mined as an ore to when it is used as a shiny, prote

jeka57 [31]

Answer: A. “electrometallurgy” followed by “electroplating”

Explanation:

Right on edge :)

8 0

3 years ago

Read 2 more answers

11. Determine the empirical formula of a compound containing 3.6 g of carbon, 0.9 g of

Norma-Jean [14]

Answer:

The empirical formula is C2H6O

Explanation:

Please see attachment for explanation on how to solve for the empirical formula.

7 0

3 years ago

For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow

lora16 [44]

Answer:

Rate constant of the reaction is $3.3\times 10^{-3} M^{-2} s^{-1}$ .

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

$R=k[A]^a[B]^b[C]^c$

Rate(R) of the reaction in trail 1 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.30 M$

$R=9.0\times 10^{-5} M/s$

$9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c$ ...[1]

Rate(R) of the reaction in trail 2 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.90 M$

$R=2.7\times 10^{-4} M/s$

$2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c$ ...[2]

Rate(R) of the reaction in trail 3 ,when :

$[A]=0.60 M,[B]=0.30 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c$ ...[3]

Rate(R) of the reaction in trail 4 ,when :

$[A]=0.60 M,[B]=0.60 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c$ ...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

$R=k[A]^2[B]^0[C]^1$

Rate constant of the reaction = k

$9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1$

$k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}$

$k=3.3\times 10^{-3} M^{-2} s^{-1}$

7 0

3 years ago

For each molecule of glucose that enters glycolysis, how many atp molecules are gained?

Semenov [28]

D. 2 ATP will be gained.

The process of Glycolysis requires 2 ATP to be activated. After glycolysis, 4 new ATPs will be produced. However, as mentioned, 2 will be used, hence only 2.

4 0

3 years ago

Read 2 more answers

if you were to compare the mass of the products and reactants in a reaction, you would find that the mass of the products is alw

Salsk061 [2.6K]

If you were to compare the mass of the products and reactants in a reaction, you would find that the mass of the products is <span>equal to the mass of the reactants.</span>

3 0

3 years ago

Which of these is NOT a type of natural force? A) gravity B) friction C) throwing D) magnetism​

Which of these is NOT a type of natural force? A) gravity B) friction C) throwing D) magnetism