Answer:
The answer of this question is element
2.03 molecules times 6.022E23 = 1.22E24
Answer:2.27 g H2O
Explanation:
Step 1. Get the limiting reagent
1.24 atm of H2 would react completely with 1.24 x (1/2) = 0.62 atm of O2, but there is more O2 present than that (0.98). O2 is in excess and H2 is the limiting reactant.
If the reaction goes to completion:
(1.24 atm H2) x (2 mol H2O / 2 mol H2) = 1.24 atm H2O vapor
n = PV / RT = (1.24 atm) x (2.5 L) / ((0.08205746 L atm/K mol) x (28 + 273)K) = 0.126 mol H2O
(0.126 mol H2O) x (18.01532 g H2O/mol) = 2.27 g H2O
Answer:
I think that A or C is the correct answer
