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Alexeev081 [22]
3 years ago
11

What is the slope of a line passing through points (-7,5) and (5,-3)?

Mathematics
1 answer:
SashulF [63]3 years ago
7 0

We can use the given points to solve for the slope.

Slope formula: y2-y1/x2-x1

-3-5/5-(-7)

-8/12

-4/6

-2/3

Best of Luck!

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It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How
omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

c \times 5 + a \times 8 = 820

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c  ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

8 0
3 years ago
Jeremiah plans on building a 5 meter long garden walkway that is paved with square stones that measure LaTeX: \frac{5}{6}5 6 met
yan [13]

Answer:

Example 1

A backyard farmer wants to enclose a rectangular space for a new garden. She has purchased 80 feet of wire fencing to enclose 3 sides, and will put the 4th side against the backyard fence. Find a formula for the area enclosed by the fence if the sides of fencing perpendicular to the existing fence have length

L.

In a scenario like this involving geometry, it is often helpful to draw a picture. It might also be helpful to introduce a temporary variable,

W, to represent the side of fencing parallel to the 4th side or backyard fence.

Since we know we only have 80 feet of fence available, we know that

L + W + L = 80, or more simply, 2L + W = 80. This allows us to represent the width, W, in terms of L: W = 80 – 2L

Now we are ready to write an equation for the area the fence encloses. We know the area of a rectangle is length multiplied by width, so

A = LW = L(80 – 2L)

A(L) = 80L – 2L2

This formula represents the area of the fence in terms of the variable length

L.

Example 2

Returning to our backyard farmer from the beginning of the section, what dimensions should she make her garden to maximize the enclosed area?

Earlier we determined the area she could enclose with 80 feet of fencing on three sides was given by the equation

A(L) = 80L – 2L2. Notice that quadratic has been vertically reflected, since the coefficient on the squared term is negative, so the graph will open downwards, and the vertex will be a maximum value for the area.

In finding the vertex, we take care since the equation is not written in standard polynomial form with decreasing powers. But we know that

a is the coefficient on the squared term, so a = -2, b = 80, and c = 0.

Finding the vertex:

h

=

−

80

2

(

−

2

)

=

20

,

k

=

A

(

20

)

=

80

(

20

)

−

2

(

20

)

2

=

800

The maximum value of the function is an area of 800 square feet, which occurs when

L = 20 feet. When the shorter sides are 20 feet, that leaves 40 feet of fencing for the longer side. To maximize the area, she should enclose the garden so the two shorter sides have length 20 feet, and the longer side parallel to the existing fence has length 40 feet.

Example 3

A ball is thrown upwards from the top of a 40 foot high building at a speed of 80 feet per second. The ball’s height above ground can be modeled by the equation

H(t) = –16t2 + 80t + 40.

What is the maximum height of the ball?

When does the ball hit the ground?

To find the maximum height of the ball, we would need to know the vertex of the quadratic.

h

=

−

80

2

(

−

16

)

=

80

32

=

5

2

,

k

=

H

(

5

2

)

=

−

16

(

5

2

)

2

+

80

(

5

2

)

+

40

=

140

The ball reaches a maximum height of 140 feet after 2.5 seconds.

To find when the ball hits the ground, we need to determine when the height is zero—when

H(t) = 0. While we could do this using the transformation form of the quadratic, we can also use the quadratic formula:

t

=

−

80

±

√

80

2

−

4

(

−

16

)

(

40

)

2

(

−

16

)

=

−

80

s

q

r

t

8960

−

32

Since the square root does not simplify nicely, we can use a calculator to approximate the values of the solutions:

t

=

−

80

−

s

q

r

t

8960

−

32

a

p

p

r

o

x

5.458

The second answer is outside the reasonable domain of our model, so we conclude the ball will hit the ground after about 5.458 seconds.Step-by-step explanation:

8 0
3 years ago
An isosceles triangle has two angles both equal to x°. The third angle is 60° bigger than either of these. Find the value of x°.
Elina [12.6K]
X+x+(x+60)=180
3x+60=180
3x=120
x=40
5 0
3 years ago
3/4g=−12<br><br><br> Help me plz
anzhelika [568]

Answer:

g=-16

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
(Will give Brainliest)
jek_recluse [69]
I believe it’s 8^3 I’m sorry if it’s wrong!!!!
5 0
3 years ago
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