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3 years ago

Help with this plz! Please❤️

Mathematics

1 answer:

sleet_krkn [62]3 years ago

3 0

Answer:

1) Qs= 24.4 cm

2) Perimeter= 72.8 m

Step-by-step explanation:

1).let qs= qos

Op is the height of the the triangle

Op= ,6.8cm

Angle ops = 180-(90+50)

Angle ops = 180-140

Angle ops = 40

Os/sin ops= op/sin pso

Os/sin 40= 6.8/sin 50

Os = sin 40(6.8)/sin50

Os= 0.6428(6.8)/0.7660

Os= 5.71

Angle oqp = 180-(90+70)

Angle oqp = 180-160.

Angle oqp = 20

Oq/sin qpo = op/sin oqp

Oq/sin 70=6.8/sin 20

Oq= sin70(6.8)/sin20

Oq= 0.9397(6.8)/0.3420

Oq= 18.68

Qs= os +oq

Qs= 5.71+18.68

Qs= 24.39

Qs= 24.4 cm

2). The other angle of the triangle

=180-90-53

= 37

Sin90 = 1

Let the length and breadth be x and y

X /sin 53 = 26

X= 26(sin53)

X= 26(0.7986)

X= 20.7636

Y/sin 37 = 26

Y= 26(0.6018)

Y= 15.6468

Perimeter= 2(x+y).

Perimeter= 2( 20.7636+15.6468)

Perimeter= 2(36.4104)

Perimeter= 72.8208 m

Perimeter= 72.8 m

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