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tensa zangetsu [6.8K]
2 years ago
15

Find the value of :x^2+2xy+y^2-3x-3y-1 have: x^2-y=y^2-x (x

"\neq" alt="\neq" align="absmiddle" class="latex-formula">y)
Mathematics
1 answer:
lidiya [134]2 years ago
7 0

Answer: The answer is x^2+2xy+2y^2–3x–3y–1

Step-by-step explanation: Move 2 to the left of y^2.

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