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3 years ago

What is log5(4*7)+log5^2 as a single log?

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

6 0

Answer with explanation:

The four options are

(A) log5 21 (B) log5 26 (C) log5 30 (D) log5 56

$\rightarrow\log_{5}(4\times 7) +\log_{5}(2)\\\\ \rightarrow \log_{5}28+\log_{5}2\\\\\rightarrow \log_{5}(28 \times 2)\\\\=\log_{5}(56)\\\\ \text{Used this property of log}\\\\ \log_{m} a+\log_{m} b=\log_{m} ab$

Option D

Darina [25.2K]3 years ago

4 0

log5(4*7)+log5^2=log5*28*25=log3500
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Which statement is not true about the data shown by the box plot below?

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Answer:

a is false

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Hence the interquartile range = 49-30

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Feel free to ask in the comments if you need any explanation why the other statements are true

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4 years ago

If f(x)=4x+7 and g(x)=x^3, what is (g°f)(-1)

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Answer:

The answer is (g°f)(-1) = 27

Step-by-step explanation:

* (g°f)(1) ⇒ means make the domain of g is the range of f

- At first find the value of f(-1)

- Take the answer and substitute it as the value of x for g

- So the range of f is the domain of g

∵ f(x) = 4x + 7

∵ The domain of f = -1 ⇒ x is the domain

∴ f(-1) = 4(-1) + 7 = -4 + 7 = 3 ⇒ f(-1) is the range

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4 years ago

Write the following expression or equation in words. x - 2y

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3 years ago

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

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4 years ago