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SOVA2 [1]
4 years ago
14

Two girls are shopping for a gift for one of their mutual friends. They are shopping together to make sure they don't buy the sa

me gift. Are these two events dependent or independent?
Mathematics
1 answer:
Stella [2.4K]4 years ago
5 0
The two events are dependent
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Daniel wanted to know his approximate score on the final exam for his mathematics class. His professor hinted that his score was
hammer [34]

Answer:   The raw score for Daniel's exam grade is 101.69.

Step-by-step explanation:

For x be any random variable.

Formula for z-score :

z=\dfrac{x-\mu}{\sigma} , where \mu = population mean

\sigma = population standard deviation.

Let x be the raw score for Daniel's exam grade.

As per given , we have

\mu=90 , \sigma=7 and z= 1.67 , put these values in the above formula , we get

1.67=\dfrac{x-90}{7}\\\\\Rightarrow\ x-90=7(1.67)=11.69\\\\\Righarrow\ x=11.69+90=101.69

Hence, the raw score for Daniel's exam grade is 101.69.

8 0
3 years ago
The following data summarizes results from 939 pedestrian deaths that were caused by accidents . If one of the pedestrian deaths
olganol [36]

Answer:

Step-by-step explanation:

Hello!

The contingency table is attached.

The total of pedestrians is 909, not 939, there are 30 accidents less in the given data.

I've calculated the asked probabilities using a total of 909.

1. The probability that the pedestrian was intoxicated or the driver was intoxicated.

Two events are mutually exclusive when the occurrence of one prevents the occurrence of the other in one single performance of the experiment. (i.e there is no intersection between the events P(A∩B)=0)

When two events are mutually exclusive, the probability of the union of both elements is equal to the sum of their individual probabilities P(A∪B)= P(A) + P(B).

When the events aren't mutually exclusive, the probability of their union is equal to the summary of their probabilities minus the probability of the intersection between these two events P(A∪B)= P(A) + P(B) - P(A∩B)

Where:

∪ is the union of both events, in colloquial language represents "or"

∩ is the union of both events, or intersection of the events, in colloquial language represents "and"

In this case P(P₁ ∪ D₁) = P(P₁) + P(D₁) - P(P₁ ∩ D₁) = \frac{306}{909} + \frac{132}{909} - \frac{81}{909} = 0.393

P₁ and D₁ are not mutually exclusive

2. The probability of the pedestrian was intoxicated or the driver was not intoxicated.

These two events aren't mutually exclusive.

P(P₁ ∪ D₂)= P(P₁) + P(D₂) - P(P₁ ∩ D₂)= \frac{306}{909} +\frac{777}{909} *-\frac{225}{909}= 0.944

I hope it helps!

3 0
3 years ago
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