3 years ago

Help please 15 points

Mathematics

1 answer:

Margaret [11]3 years ago

7 0

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25) Which graph represents the equation below? ) = w+ 2 A ܠܐ 5 4 (2, 4) 3 2 1 (-2,0) -5 -4 -3 -2 -1 0 -1 x 1 2 3 4 5 -2 -3 -4 -5

victus00 [196]

Answer:

Can you attach a pic please ?

Step-by-step explanation:

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3 years ago

Help please!! Stuck on this question!! ∠ABC is adjacent to ∠CBD. If the m∠ABC=4x+23, m∠CBD=6x+7, and m∠ABD=130°, what is the mea

Ulleksa [173]

Answer:

63 degrees

Step-by-step explanation:

add 4x + 23 and 6x + 7, then equal that to 130. When you find x, plug it into 4x+23 and get 63.

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3 years ago

6h+(-7.3d)-13+5d-2.6h=? PLEASE HELP ASAP

Strike441 [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

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3 years ago

Given the number 2464829438 what is the next number?

malfutka [58]

2464829438
The next number is 2,464,829,439

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3 years ago

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