Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So
Rounding up
We need a sample size of 564.
Answer: 22
explanation: the easiest way is to separate one of the diagonals into a triangle and use the pythagorean theorem.
a^2 + b^2 = c^2
4^2 + 3^3 = c^2
16 + 9 = c^2
25 = c^2
5 = c
you now know that both of the diagonals have a length of 5.
by counting the units on the two straight, you know that their length is 6.
6 + 6 + 5 + 5 = 22
Answer:
Answer: Osvoldo did not meet his goal.
Step-by-step explanation:
Total carbohydrate ate by Osvoldo = 220 g
carbohydrate from grains = 55 g
Percentage of carbohydrate of grain is
\begin{gathered}=\dfrac{\text { carbohydrate taken from grains}}{\text {Total carbohydrate}} \times 100\\\\= \dfrac{55}{220} \times 100= 25 \%\end{gathered}
=
Total carbohydrate
carbohydrate taken from grains
×100
=
220
55
×100=25%
Goal of getting carbohydrate from grains = at least 30%
but he ate only 25% of carbohydrate
Hence, Osvoldo did not meet his goal as he ate less carbohydrate than his goal.
The equation for area of a triangle is A= 1/2bh so a=1/2(12cm)(9.6cm)
Volume of a cone = <span>πr^2(h/3)
r=6
h=27
v = </span><span>π(6^2)27/3
v = </span><span>π (36)(9)
v=</span><span>π324 in. cubed
or
v=1,017.36 in. cubed </span>
