9514 1404 393
Answer:
57.2 ft
Step-by-step explanation:
The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
cos(G) = IG/GH
GH = IG/cos(G) = (57 ft)/cos(5°)
GH ≈ 57.2 ft
Answer:
A
Step-by-step explanation:
Hopefully this helps
When you make the product of a binomial of the kind x + a times other binomial that is of the kind x - a, you obtain another binomial (not a trinomial), so any example with that form will be a counterexample that disproves the conjecture:
(x + a) * (x - a) = x^2 - a^2
For example, (x +3) * (x - 3) = x^2 - 9. So, not always the product of two binomials is a trinomial.
The correct model of the height of rocket above water is;
h(t) = -16t² + 96t + 112
Answer:
time to reach max height = 3 seconds
h_max = 256 ft
Time to hit the water = 7 seconds
Step-by-step explanation:
We are given height of water above rocket;
h(t) = -16t² + 96t + 112
From labeling quadratic equations, we know that from the equation given, we have;
a = -16 and b = 96 and c = 112
To find the time to reach maximum height, we will use the vertex formula which is; -b/2a
t_max = -96/(2 × -16)
t_max = 3 seconds
Thus, maximum height will be at t = 3 secs
Thus;
h_max = h(3) = -16(3)² + 96(3) + 112
h_max = -144 + 288 + 112
h_max = 256 ft
Time for it to hit the water means that height is zero.
Thus;
-16t² + 96t + 112 = 0
From online quadratic formula, we have;
t = 7 seconds
Answer:
-1 this equation is in slope intercept for y=mx+b. the slope is variable m, which in this case is -1. the one is always invisible in front of variable
