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Vera_Pavlovna [14]
2 years ago
15

Which equation choice could represent the graph show below?

Mathematics
1 answer:
12345 [234]2 years ago
5 0

Answer:

A

Step-by-step explanation:

Hopefully this helps

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Four glasses of milk and 2 snack bars have a total of 72 carbohydrates​ (carbs), and 2 glasses of milk and 3 snack bars have a t
Travka [436]

One glass of milk has 11 carbs and one snack bar has 14 carbs.

Step-by-step explanation:

Let,

Glass of milk = x

Snack bar = y

According to given statement;

4x+2y=72   Eqn 1

2x+3y=64   Eqn 2

Multiplying Eqn 2 by 2

2(2x+3y=64)\\4x+6y=128\ \ \ Eqn\ 3

Subtracting Eqn 1 from Eqn 3

(4x+6y)-(4x+2y)=128-72\\4x+6y-4x-2y=56\\4y=56

Dividing both sides by 4

\frac{4y}{4}=\frac{56}{4}\\y=14

Putting y=14 in Eqn 1

4x+2(14)=72\\4x+28=72\\4x=72-28\\4x=44

Dividing both sides by 4

\frac{4x}{4}=\frac{44}{4}\\x=11

One glass of milk has 11 carbs and one snack bar has 14 carbs.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/5461619
  • brainly.com/question/5510873

#LearnwithBrainly

6 0
2 years ago
An airplane ascends such that its gain h in altitude is proportional to the square root of the change x in horizontal distance t
Mazyrski [523]

Answer:velocity=185 m/s

Step-by-step explanation:

So make k the subject of the formula by divide both by sqrt(x)

h= k × sqrt(x)

k=h/sqrt(x)

k=256 / sqrt(256)

k=256 / 16

k=16

So now substitute the value of k :

h= 16 × sqrt (x)

Then differentiate:

=(1/2 × sqrt(x))× 16

=16/(2×sqrt(x)

=8/sqrt(x)

Then

= 8/sqrt(x) × 370

=8/ sqrt(256) × 370

=8/16 × 370

velocity=185 m/s

6 0
2 years ago
Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%
Nataly [62]

Step-by-step explanation:

<h3>\sec \alpha  \sqrt{1 -  \sin ^{2}   \alpha }  = 1</h3>

Prove the LHS

Using trigonometric identities

That's

<h3>\cos ^{2}  \alpha  = 1 -  \sin^{2}  \alpha</h3>

<u>Rewrite the expression</u>

We have

<h3>\sec \alpha  \sqrt{ \cos^{2} \alpha  }</h3>

<h3>\sqrt{ { \cos }^{2}  \alpha }  =  \cos \alpha</h3>

So we have

<h3>\sec  \alpha  \times  \cos \alpha</h3>

Using trigonometric identities

<h3>\sec \alpha  =  \frac{1}{ \cos \alpha }</h3>

<u>Rewrite the expression</u>

That's

<h3>\frac{1}{\cos \alpha }  \times  \cos \alpha</h3>

Reduce the expression with cos a

We have the final answer as

<h2>1</h2>

As proven

Hope this helps you

7 0
2 years ago
Write your answer in simple solution (4x^3+2x+6)+(2x^3-x^2+2)
Ket [755]
The answer in simple solution is 6x^3-x^2+2x+8
4 0
1 year ago
WILL GIVE BRAINLIEST!!
charle [14.2K]
The answer is C: 16.5 square units, because the formula for the area is base times height over 2, and the height is 11; base is 3; 3 • 11 = 33; 33/2=16.5
6 0
2 years ago
Read 2 more answers
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