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3 years ago

Fill in the missing digits to complete the patern 5, 62, 2, 2

Mathematics

1 answer:

hichkok12 [17]3 years ago

5 0

165414618182551iqiqiqii

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Using the completing-the-square method, rewrite f(x) = x2 + 10x + 7 in vertex form

mr Goodwill [35]

Answer:

f(x) = (x - (-5))^2 + (-18)

Step-by-step explanation:

Given:

f(x) = x^2 + 10x + 7

Rewrite f(x) in vertex form

Solution:

f(x) = ax^2 + bx + c is a quadratic function.

The vertex form of f(x) is a(x - h)^2 + k, where (h, k) is the vertex.

=> f(x) = x^2 + 10x + 7

= x^2 + 10x + 25 - 18

= (x + 5)^ - 18

= (x - (-5))^2 + (-18)

=> f(x) can be rewritten in form of a(x - h)^2 + k, where (h, k) is the vertex, with a = 1, h = -5, k = -18

6 0

3 years ago

Use slope-intercept form, y = mx + b, to find the value for the y-intercept (b) of a line that has a slope of 6 and passes throu

stiks02 [169]

Answer:

-23, $y=6x-23$

Step-by-step explanation:

We need slope intercept form but do not have the needed information. We will gather this information by using point slope form. The point-slope formula is $y -y_{1} =m(x -x_{1})$ where we substitute a point (x,y) for $(x_{1},y_{1})$ .

We have slope represented as m=6 and (3, -5). We input m and $x_{1} =3\\y_{1}=-5$ .

$y-(-5)=6(x-3)\\y+5=6(x-3)$

We now simplify the parenthesis and solve for y to have slope intercept form.

$y+5=6(x-3)\\y+5=6x-18\\y+5-5=6x-18-5\\y=6x-23$

The y-intercept is b of slope intercept form y=mx+b. Here b=-23.

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=9y%20%3D%209%20%5Ctimes%20" id="TexFormula1" title="9y = 9 \times " alt="9y = 9 \times " align

WINSTONCH [101]

What are you solving for? For y: y=x or for x: x=y

6 0

2 years ago

Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent f

Ksivusya [100]

Answer: The weight of X is $33\dfrac{1}{3}\%$ of weight of mixture.

Step-by-step explanation:

Since we have given that

Percentage of seed mixture X for ryegrass = 40%

Percentage of seed mixture Y for ryegrass = 25%

If a mixture of X and Y contains 30 percent ryegrass,

Let total seed mixture be 100

So, for seed X = x

For seed Y = 100-x

So, According to question,

$0.4x+0.25(100-x)=30\\\\0.4x+25-0.25x=30\\\\0.15x=30-25\\\\0.15x=5\\\\x=\dfrac{5}{0.15}\\\\x=\dfrac{100}{3}$

So, weight of mixture X is given by

$\dfrac{\text{Weight of X}}{\text{Weight of mixture}}\times 100\\\\=\dfrac{\dfrac{100}{3}}{100}\times 100\\\\=\dfrac{100}{3}\%\\\\=33\dfrac{1}{3}\%$

Hence, the weight of X is $33\dfrac{1}{3}\%$ of weight of mixture.

6 0

2 years ago

Multiply -5/3 and -9/1

KonstantinChe [14]

It’s 15!! hope this helps :))))

6 0

2 years ago

Read 2 more answers