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iris [78.8K]
3 years ago
15

Which best describes Imara’s error?

Mathematics
1 answer:
Sati [7]3 years ago
7 0
<h2>Answer:</h2>

The statement that best describes Imara's error is:

                         Option: D

  D). She did not find the side lengths of the square with an area of 625.

<h2>Step-by-step explanation:</h2>

Imara correctly did the previous calculation.

i.e. she correctly determined the area of square with side length 20 units (as 400 square units) and 15 units (i.e. 225 square units)

But when she sum the area of two squares then it won't give the length of hypotenuse it would give the  area of a square.

                      Hence, the correct answer is:

                              Option: D

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K is the midpoint of JL JK=3x-1 and KL=2x+8 find JL
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Answer:

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Step-by-step explanation:

It is given in the question that K is the midpoint of JL.

So, JK = KL ......... (1)

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Hence, JL = JK + KL = 26 + 26 = 52. (Answer)

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