Question

The product of two consecutive positive integers is 29 more than their sum. Find the integers

Answer 1

The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5    then: (x+1)=-5+1=-4  This is not the solution.
x₂=(1+11)/2=6    then: (x+1)=6+1=7    This solution is right.

Answer: the numbers would be 6 and 7.