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Darya [45]
3 years ago
14

PLEASE ANYONE HELP!!!!

Mathematics
1 answer:
meriva3 years ago
3 0
The output is 1
How I helped :D
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Final numeric grades in a certain course are normally distributed with a mean of 72.3 and a standard deviation of 6.4. The profe
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Answer:

The minumum numeric grade you have to earn to obtain an A is 81.29.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 6.4

The professor curves the grades so that the top 8% of students will receive an A. What is the minumum numeric grade you have to earn to obtain an A?

The minimum numeric value is the value of X when Z has a pvalue of 1-0.08 = 0.92. So it is X when Z = 1.405.

So

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 72.3}{6.4}

X - 72.3 = 1.405*6.4

X = 81.29

The minumum numeric grade you have to earn to obtain an A is 81.29.

6 0
3 years ago
PLEASE HELP QUICK
valentinak56 [21]

Answer: 28 in.

Step-by-step explanation:

its simple

7 0
4 years ago
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