Divide the bottom number with the top number
we know that
The measurement of the external angle is the semi-difference of the arcs it comprises.
so
Step 
<u>Find the measure of the arc AJ</u>
m∠BDE=![\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ BE]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-measure%5C%20arc%5C%20BE%5D)
in this problem we have
m∠BDE=
substitute in the formula
=![\frac{1}{2} *[measure\ arc\ AJ-38\°]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-38%5C%C2%B0%5D)
=![[measure\ arc\ AJ-38\°]](https://tex.z-dn.net/?f=%5Bmeasure%5C%20arc%5C%20AJ-38%5C%C2%B0%5D)
Step 
<u>Find the measure of the arc FH</u>
m∠FGH=![\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-measure%5C%20arc%5C%20FH%5D)
in this problem we have
m∠FGH=
substitute in the formula
=![\frac{1}{2} *[112\°-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5B112%5C%C2%B0-measure%5C%20arc%5C%20FH%5D)
=![[112\°-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5B112%5C%C2%B0-measure%5C%20arc%5C%20FH%5D)
therefore
<u>the answer is</u>
the measure of the arc FH is 
3/25 and 7 5/7 are the answers. These are some ugly fractions!
2 - 1 + 5
= 6
Hope his help
Answer:
Aditya evaluates the numerator of the expression when x = –1. He finds the remainder of the division to be –1
Step-by-step explanation:
– 12x¹⁷+ 3x⁵ – 9x² – 1 / x + 1
To obtain the answer to question, let us apply the remainder theorem. This is illustrated below:
Assume:
x + 1 = 0
Subtract 1 from both side
x + 1 – 1 = 0 – 1
x = – 1
Next, we shall substitute the value of x into – 12x¹⁷+ 3x⁵ – 9x² – 1. This is illustrated below:
– 12x¹⁷+ 3x⁵ – 9x² – 1
x = – 1
– 12(–1)¹⁷+ 3(–1)⁵ – 9(–1)² – 1
– 12(–1) + 3(–1) – 9(1) – 1
12 – 3 – 9 – 1
= –1
Thus, using the remainder theorem,
– 12x¹⁷+ 3x⁵ – 9x² – 1 / x + 1 will result to –1
