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Ainat [17]
2 years ago
13

Pls tell the answer pls

Mathematics
2 answers:
ehidna [41]2 years ago
8 0
It’s C I’m pretty sure
Crank2 years ago
6 0

Answer:

The correct answer is C

Step-by-step explanation:

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Which pairs of angles in the figure below are vertical angles?
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Answer:

thew answer is A DTN AND ATP

Step-by-step explanation:

its the correct answer and most reasonable

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Does anyone one know how to make a factor a decimal on the calculator
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Step-by-step explanation:

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Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
3. Kevin went to the nursery and bought a 5 ft tall tree. After planting the tree, Kevin made a table to record the height, h, o
Rina8888 [55]

Answer:

uh where's the rest of the question?

Step-by-step explanation:

3 0
3 years ago
WORDED QUADRATIC EQUATION!!! PLS HELP <br><br> MOSTLY NUMBER 5 PLS
pav-90 [236]

Answer:

7,11

Step-by-step explanation:

The width is x. x+4= the length. The area is side times side, so it’s

x × (x+4) = 77

We can simplify this to:

x × x + x × 4 = 77

x^2 + 4x = 77

x^2 + 4x - 77 = 0 This is a quadratic equation. So we can solve using the quadratic formula:

x = \frac{-4\pm\sqrt{4^2-4\cdot1\cdot-77}}{2\cdot1} ->

\frac{-4\pm18}{2}

\frac{14}{2} \implies7

That’s the positive solution and that’s x, the width. So the width is 7 and the length is 7+4=11

3 0
2 years ago
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