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monitta
3 years ago
7

An anagram is a word or a phrase made by transposing the letters of another word or phrase; for example, "parliament" is an anag

ram of "partial men," and "software" is an anagram of "swear oft." Write a program that figures out whether one string is an anagram of another string. The program should ignore white space and punctuation.
Computers and Technology
1 answer:
Sliva [168]3 years ago
4 0

Answer:

Anagram

Explanation:

public class Anagram {

   public static boolean areAnagrams(String string1,

                                     String string2) {

       String workingCopy1 = removeJunk(string1);

       String workingCopy2 = removeJunk(string2);

    workingCopy1 = workingCopy1.toLowerCase();

    workingCopy2 = workingCopy2.toLowerCase();

    workingCopy1 = sort(workingCopy1);

    workingCopy2 = sort(workingCopy2);

       return workingCopy1.equals(workingCopy2);

   }

   protected static String removeJunk(String string) {

       int i, len = string.length();

       StringBuilder dest = new StringBuilder(len);

   char c;

    for (i = (len - 1); i >= 0; i--) {

        c = string.charAt(i);

        if (Character.isLetter(c)) {

         dest.append(c);

        }

    }

       return dest.toString();

   }

   protected static String sort(String string) {

    char[] charArray = string.toCharArray();

    java.util.Arrays.sort(charArray);

       return new String(charArray);

   }

   public static void main(String[] args) {

       String string1 = "Cosmo and Laine:";

       String string2 = "Maid, clean soon!";

       System.out.println();

       System.out.println("Testing whether the following "

                        + "strings are anagrams:");

       System.out.println("    String 1: " + string1);

       System.out.println("    String 2: " + string2);

       System.out.println();

       if (areAnagrams(string1, string2)) {

           System.out.println("They ARE anagrams!");

       } else {

           System.out.println("They are NOT anagrams!");

       }

       System.out.println();

   }

}

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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

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String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

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for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

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else

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if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

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// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

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int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

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System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

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System.out.println(s3.substring(4, 8));

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Answer:

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Explanation:

public class Card

{

   String Suit;

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       self.value = value;

       // Check Suits value

       if ((Suit == "hearts") || (Suit == "spades") || (Suit == "clubs") || (Suit == "diamonds"))

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        }

   }

   public String getSuit() {

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   }

   public int getValue() {

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