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Zigmanuir [339]
2 years ago
5

Solve the equations if possible * -5×=×+6(1-×) *(2×-5)²=(2×-1)(2×+1)-10(2×-1)

Mathematics
1 answer:
Allushta [10]2 years ago
8 0
-5x = x + 6(1-x)

-5x = x + 6(1) + 6(-x)
-5x = x + 6 -6x
-5x = x - 6x + 6
-5x = -5x + 6
-5x + 5x = 6
0 = 6  Not equal. No solution.

(2x-5)² = (2x-1)(2x+1) -10(2x-1)
(2x-5)(2x-5) = (2x-1)(2x+1) - 20x + 10
2x(2x-5)-5(2x-5) = 2x(2x+1)-1(2x+1) - 20x + 10
4x² - 10x -10x + 25 = 4x² + 2x - 2x -1 - 20x + 10
4x² - 20x + 25 = 4x² - 20x - 1 + 10
4x² - 20x + 25 = 4x² - 20x - 9

Not equal. No solution.

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Answer:

The answer to your question is below

Step-by-step explanation:

Domain is the values of x the function can take   D = (-2, 2]

Range is the values of y the function can take     R = [-5, 4]

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c) From the graph we got f(1) = -5

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