Answer:
400 ft
Step-by-step explanation:
Let the distance traveled = d
Let the time taken = t
d α t^2
d = kt^2
k = d /t^2
When d = 100 and t = 2.5secs
k = 100/ (2.5)^2
k = 16
d = 16t^2
When t = 5secs
d = 16(5)^2
d = 16 * 25
d = 400 ft
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.
f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
Answer:
1st: 5x
2nd: 6ft
Step-by-step explanation:
I really don't know how just got the answer right.