Answer:-25176.5
Step-by-step explanation:
Answer:
8.1 x 10^7 would be you answer.
9514 1404 393
Answer:
- 12 boxes
- 10 pencils, 9 notebooks
Step-by-step explanation:
a) The number of boxes will be the greatest common divisor (GCD) of the numbers 120 and 108. That number is 12.
120 = 12×10
108 = 12×9 . . . . 12 is the greatest common divisor
Matthew can make 12 boxes with equal numbers of the items.
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b) 120 pencils divided by 12 will be 10 pencils per box.
108 notebooks divided by 12 will be 9 notebooks per box.
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<em>Additional comment</em>
It helps to be familiar with multiplication tables up to about 12×12.
The GCD can always be found using Euclid's algorithm. Look at the remainder when the larger number is divided by the smaller. If it is not zero, then replace the larger number with the remainder and repeat. If the remainder is zero, the divisor is the GCD.
Here, we have ...
120/108 = 1 r 12.
108/12 = 9 r 0 ⇒ 12 is the GCD
Answer:
52%
Step-by-step explanation:
Answer:
A customer who sends 78 messages per day would be at 99.38th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average of 48 texts per day with a standard deviation of 12.
This means that 
a. A customer who sends 78 messages per day would correspond to what percentile?
The percentile is the p-value of Z when X = 78. So



has a p-value of 0.9938.
0.9938*100% = 99.38%.
A customer who sends 78 messages per day would be at 99.38th percentile.