Question

Function f is defined by f(x)=3/2x+c. If f(6)=1, what is the value of f(c)?

Answer 1

Answer:

C = - 8

Step-by-step explanation:

$f(x) = \frac{3}{2} x + c \\ \\ plug \: x = 6 \\ \\ f(6) = \frac{3}{2} \times 6 + c \\ \\ f(6) = 3 \times 3 + c \\ \\ f(6) = 9+ c \\ \\ \therefore \: 1 = 9 + c \: \{ \because \: f(6) = 1 \} \\ \\ 1 - 9 = c \\ \\ \huge \red{ \boxed{ c = - 8}}\\\\f(c) =\frac{3}{2} c +(-8)\\\\\huge \orange { \boxed{ f(c) =\frac{3}{2} c -8}}$