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lara31 [8.8K]
3 years ago
11

The variables for this experiment include the height of the track and the speed of the car. Use the drop-down menus to complete

the sentences and identify the independent and dependent variables.
Chemistry
1 answer:
nekit [7.7K]3 years ago
3 0

Answer:

we dont know the options

Explanation:

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What is the mass of an original 5.60-gram sample of iron-53 that remains unchanged after 25.53 minutes?
olga_2 [115]
Answer is 0.7 g

Reason: Given: mass of Fe = 5.60 gWe know that, half life of Fe-53 = t1/2 (Fe-53) = 8.51 min.
Thus, after 25.53 mins, number of half life passed = 25.53/8.51= 3

Now, Amount left after first half life = 5.60g/2 = 2.80 g
Amount left after second half life = 2.80g/2 = 1.40 g
Amount left after third half-life = 1.40g/2 = 0.7g.
4 0
4 years ago
HELPPPPP!!<br><br>How can more water vapor get cold over one side of an island?
Veronika [31]

Answer:

Troposphere and Atmosphere In this chapter, students learn that water vapor condenses as it moves higher to where the atmosphere is colder. This idea helps students explain why more rain forms over West Ferris than East Ferris.

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8 0
3 years ago
What mass of N2 will be needed to produce 31.5 grams of N2O5?
SCORPION-xisa [38]

Answer: d) 16.34 grams

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  

\text{Moles of} N_2O_5=\frac{31.5g}{108.01g/mol}=0.292moles

4N_2+5O_2\rightarrow 2N_2O_5  

According to stoichiometry :

As 2 moles of N_2O_5 are produced by= 4 moles of N_2

Thus 0.292 moles of N_2O_5 are produced by=  =\frac{4}{2}\times 0.292=0.584moles of N_2

Mass of N_2=moles\times {\text {Molar mass}}=0.584moles\times 28g/mol=16.34g

Thus 16.34 g of N_2 will be needed

6 0
3 years ago
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