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Damm [24]
3 years ago
14

The number of oxygen atoms (O) in 0.24g of calcium carbonate CaCO3

Chemistry
1 answer:
Sveta_85 [38]3 years ago
8 0

Answer:

0.036  × 10²³ oxygen atoms

Explanation:

Given data:

Mass of compound = 0.24 g

Number of oxygen atoms = ?

Solution:

First of all we will calculate the number of moles of compound.

number of moles = mass/ molar mass

Number of moles = 0.24 g/ 100.1 g/mol

Number of moles = 0.002 mol

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole of CaCO₃ contain 3 moles of oxygen atom.

0.002 mol × 3 = 0.006 moles of oxygen atoms.

Number of oxygen atoms:

1 mole = 6.022 × 10²³ number of oxygen atoms

0.006 mol ×  6.022 × 10²³ f oxygen atoms / 1 mol

0.036  × 10²³ oxygen atoms

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7 0
3 years ago
How many grams are in 3.14 x 1015 molecules of CO?
Vesnalui [34]

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

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Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

5 0
3 years ago
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